折半查找

Oliver xu

有一个数组A[10],里面存放了10个整数,顺序递增,A[10]={2,3,5,7,8,10,12,15,19,21},任意输入一个数字n,用折半查找法找到n位于数组中的位置,如果n不属于数组A,显示错误提示

算法分析:折半查找 代码实现:

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#include <stdio.h>

int bin_search(int A[], int n, int key)
{
int mid,high,low;
low = 0;
high = n-1;
while(low<=high)
{
mid=(high+low)/2;
if(a[mid]==key)
{
return mid;
}
if(a[mid]>key)
{
high=mid-1;
}
if(a[mid]<key)
{
low=mid+1;
}
}
return -1;
}

int main()
{
int A[10] = {2,3,5,7,8,10,12,15,19,21}
int i,n,addr;
printf("The contents of the Array A[10] are\n");
for(i=0;i<10;i++)
{
printf("%d ", A[i]);
}
printf("\nPlease input a interger for search\n");
scanf("%d",&n);
addr = bin_search(A,10,n);
if(addr != -1)
{
printf("%d is at the %dth unit is array A\n ",n,addr);
}
else
{
printf("There is no %d in array A\n",n);
}

  • 标题: 折半查找
  • 作者: Oliver xu
  • 创建于 : 2018-08-26 11:24:43
  • 更新于 : 2024-12-21 21:05:39
  • 链接: https://blog.oliverxu.cn/2018/08/26/折半查找/
  • 版权声明: 本文章采用 CC BY-NC-SA 4.0 进行许可。
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折半查找